Question

The length of a rectangle is 8 m more than the width if the perimeter is 128 m what are the length and the width

Answer 1

Perimeter: 2 * width + 2 * length

Divide 128 by 4

128/4 = 32

Subtract 4

32 - 4 = 28

Add 4

32 + 4 = 36

The width is equal to 28, and the length is equal to 36

We can verify this by using the original equation

28 * 2 + 36 * 2 = 128