Note that both 121 and 289 are perfect fractions: 121 = 11^2 and 289 = 17^2.
Thus,
121 11^2
------- = ---------- = (11/17)^2.
289 17^2
The square root of this is merely 11/17.
Answer:
[tex]\frac{11}{17}[/tex].
Step-by-step explanation:
Given : [tex]\frac{121}{289}[/tex].
To find : square root.
Solution : We have given [tex]\sqrt{\frac{121}{289}}[/tex].
We can write the
121 as 11 *11 .
289 as 17 * 17.
By the radical rule : [tex]\sqrt{a*a} =a[/tex].
So, [tex]\sqrt{\frac{11*11}{17*17}}[/tex] = [tex]\frac{11}{17}[/tex].
Therefore, [tex]\frac{11}{17}[/tex].
