beatrizho0328
beatrizho0328 beatrizho0328
  • 16-09-2018
  • Mathematics
contestada

Plsss help me on this one!!!!

Plsss help me on this one class=

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KOAL
KOAL KOAL
  • 16-09-2018

m∠ADC=m∠ADB + m∠BDC

134°=5x+4 + 7x-2

134°= 12x+2

-2            -2

132°=12x

/12     /12

11°=x

m∠BDC = 7x-2 = 7(11) -2 = 77-2 = 75°


m∠BDC = 75°

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