Respuesta :

Make use of the relationships you know about angles inscribed in a circle. You also know the degree measure of a full circle is 360°, so a semicircle is 180°.

13) The sum of the two arcs is 180°, so you have

... (13x -10) + (7x -10) = 180

... 20x -20 = 180

... 20x = 200

... x = 10

Then arc NM is 7·10 -10 = 60 degrees, and angle NLM is half that.

∠NLM = 30°

_____ _____

14) You know that angle FGH is half the measure of arc FAH, and angle FAH is half the measure of arc FGH. Together these facts tell you

... 2∠FGH + 2∠FAH = arc FAH + arc FGH = 360°

... ∠FGH + ∠FAH = 180° . . . . . opposite angles of an inscribed quadrilateral are supplementary—a nice fact to remember

... (21x -2) + (38x +5) = 180

... 59x = 177 . . . . . . . . . . . . . . collect terms, subtract 3

... x = 3 . . . . . . . . . . . . . . . . . . divide by 59

∠FAH = 38x +5 = 38·3 +5 = 119

Arc FGH has twice this measure: 238°.

Answer:

Step-by-step explanation:

13) The sum of the two arcs is 180°, so you have

... (13x -10) + (7x -10) = 180

... 20x -20 = 180

... 20x = 200

... x = 10

Then arc NM is 7·10 -10 = 60 degrees, and angle NLM is half that.

∠NLM = 30°

_____ _____

14) You know that angle FGH is half the measure of arc FAH, and angle FAH is half the measure of arc FGH. Together these facts tell you

... 2∠FGH + 2∠FAH = arc FAH + arc FGH = 360°

... ∠FGH + ∠FAH = 180° . . . . . opposite angles of an inscribed quadrilateral are supplementary—a nice fact to remember

... (21x -2) + (38x +5) = 180

... 59x = 177 . . . . . . . . . . . . . . collect terms, subtract 3

... x = 3 . . . . . . . . . . . . . . . . . . divide by 59

∠FAH = 38x +5 = 38·3 +5 = 119

Arc FGH has twice this measure: 238°.