Respuesta :
The solution contains potassium nitrate (KNO3) in water (H2O)
The molar mass of KNO3 = 101 g/mol
The molar mass of H2O = 18 g/mol
Mole fraction of KNO3 = 0.0194
Therefore mole fraction of H2O = 1 - 0.0194 = 0.9806
Total mass of the solution = KNO3 + H2O
= 0.0194 moles * 101 g/mol + 0.9806 moles * 18 g/mol
= 1.9594 g + 17.6508 = 19.6102 g
Volume of the solution = Mass of solution/density
= 19.6102 g/ 1.0627 g.ml-1 = 18.453 ml = 0.01845 L
Molarity of KNO3 = moles of KNO3/volume of solution
= 0.0194 mole/0.01845 L = 1.05 M
The molarity of the potassium nitrate (KNO₃) in an aqueous solution is 1.05 M.
What is mole fraction?
Mole fraction is define as the number of moles of solute present in total moles of solution.
In the given question, potassium nitrate (KNO₃) is present in water (H₂O).
We know that, mole fraction of KNO₃ + mole fraction of H₂O = 1
Mole fraction of KNO₃ = 0.0194 (given)
Mole fraction of H₂O= 1 - 0.0194 = 0.9806
Now total mass of the solution can be calculated by using the formula n=W/M, where
n = no. of moles
W = wanted or given mass
M = molar mass
Total mass of the solution = mass of KNO₃+ mass of H2O
= 0.0194 moles × 101 g/mol + 0.9806 moles × 18 g/mol
= 1.9594 g + 17.6508 = 19.6102 g
Volume of the solution can be calculated as:
Volume = Mass of solution/density = 19.6102 g/1.0627 g/ml = 18.453 ml = 0.01845 L
Now molarity of KNO₃ will be calculated as:
M = n/V
M = 0.0194 mole/0.01845 L = 1.05 M
Hence, molarity of the solution is 1.05 M.
To know more about mole fraction, visit the below link:
https://brainly.com/question/14498215
