Answer:- [tex]1s^22s^22p^4[/tex] .
Explanation:- Atomic number for fluorine(F) is 9 and it's electron configuration is [tex]1s^22s^22p^5[/tex] . [tex]F^+[/tex] is formed when F loses one electron from it's valence shell.
[tex]F\rightarrow F^++1e^-[/tex]
Second shell is the valence shell for fluorine and so it loses one electron from 2p to form [tex]F^+[/tex] and the electron configuration of the ion becomes [tex]1s^22s^22p^4[/tex] .