5 moles of C₃H₃N
The Balance Chemical Equation is as follow,
4 C₃H₆ + 6 NO → 4 C₃H₃N + 6 H₂O + N₂
Step 1: Calculate the Limiting Reagent,
According to Balance equation,
4 moles of C₃H₆ reacts with = 6 moles of NO
So,
5 moles of C₃H₆ will react with = X moles of NO
Solving for X,
X = (5 mol × 6 mol) ÷ 4 mol
X = 7.5 mol of NO
It means 5 mol of C₃H₆ requires 7.5 mol of NO, while we are provided with 9 mol NO which is in excess. Therefore, C₃H₆ is the limiting reagent and will control the yield of products.
Step 2: Calculate amount of C₃H₃N produced,
According to equation,
4 moles of C₃H₆ produces = 4 moles of C₃H₃N
So,
5 moles of C₃H₆ will produce = X moles of C₃H₃N
Solving for X,
X = (5 mol × 4 mol) ÷ 4 mol
X = 5 moles of C₃H₃N