Respuesta :
The circumference must be within half the difference of the average of those two numbers:
... |c -28.75| ≤ 0.25 . . . . where c is the circumference in inches
Answer:
[tex]|C-28.75|\leq 0.5[/tex]
Step-by-step explanation:
Let C represent circumference of the ball.
We have been given that circumference of a basketball for college women must be from 28.5 in. to 29.0 in. We are asked to write an absolute value inequality for the given scenario.
[tex]|\text{Actual}-\text{Ideal}|\leq \text{Tolerance}[/tex]
[tex]\text{Tolerance}=29.0-28.5=0.5[/tex]
Ideal will be average of both circumference.
[tex]\text{Ideal}=\frac{29.0+28.5}{2}[/tex]
[tex]\text{Ideal}=\frac{57.5}{2}[/tex]
[tex]\text{Ideal}=28.75[/tex]
Upon substituting our given values, we will get:
[tex]|C-28.75|\leq 0.5[/tex]
Therefore, our required absolute value inequality would be [tex]|C-28.75|\leq 0.5[/tex].