Respuesta :
Solution : Emperical Formula = [tex]CH_{3}[/tex]
Emperical Formula - A formula that gives the simplest whole number ratio of atom in a compound.
In the question percentages are given then assume that the total mass is 100grams so that the mass of each element is equal to the percentage given.
Given : 80.0g Carbon
20.0g Hydrogen
First convert the given masses into moles.
[tex]80.0g\text{ C} \times \frac{1 g/mole \text{ C}}{12.0 g/mole \text{ C}}= 6.66\text{mole of C}[/tex]
[tex]20.0g\text{ H} \times \frac{1 g/mole \text{ H}}{1 g/mole \text{ H}}= 20.0\text{mole of H}[/tex]
Value of each mole divided by the smallest number of moles and then round off.
Moles ratio of the element are
[tex]\frac{6.66}{6.66}\text{mole of C}= 1[/tex]
[tex]\frac{20.0}{6.66}\text{mole of C}= 3[/tex]
This is the mole ratio of the elements and is repersented by the subscript in the emperical formula.
Emperical Formula = [tex]CH_{3}[/tex]
