we are given
f(x) is a odd function
so, [tex]f(-x)=-f(x)[/tex]
[tex]-f(x)=f(-x)[/tex]
now, we are given
[tex]\lim _{x\to 0+}f\left(x\right)=3[/tex]
Let's multiply both sides by -1
[tex]-\lim _{x\to 0+}f\left(x\right)=-3[/tex]
[tex]\lim _{x\to 0+}-f\left(x\right)=-3[/tex]
we have
[tex]-f(x)=f(-x)[/tex]
[tex]\lim _{x\to 0+}f\left(-x\right)=-3[/tex]
now, let's consider y=-x
so, when x--->0+
but for y=-x
y--->0-
now, we can plug it
[tex]\lim _{y\to 0-}f\left(y\right)=-3[/tex]
replace y as x
we get
[tex]\lim _{x\to 0-}f\left(x\right)=-3[/tex].................Answer