Answer:
The magnitude of the acceleration is 1.2 m/s2 and the direction is positive, upward.
Explanation:
When a parachute opens, the air exerts a large drag force on it. This upward force is initially greater than the weight of the sky driver, and, thus, slow him down. It means, if the drag force is greater than the weight, acceleration should be upward and positive to slows him.
We have the weight W = 915 N of the sky driver. This is negative, due to the direction.
The drag force D = 1027 N. This is positive, due to the direction upward. The mass of the sky driver is m=93.4 kg with an unknown acceleration a.
The Newton laws shoued us:
∑F = m*a
D - W = m*a
1027 - 915 = 93.4*a
93.4*a = 112
a = 112/93.4
a = 1.2 m/s2
Finally, we can conclude that The magnitud of the acceleration is 1.2 m/s2 and the direction is positive, upward.
