Question

A line passes through the point (-1,4) and the point (3,4) what is the equation of the line.

Answer 1

M=y2-y1/x2-x1  (-1,4)(3,4)  M=4-4/3-(-1) M= 0/4 M=0  Now get one of the points  (3,4)  Y=mx+b 4=0(3)+b 4=b  Equation  Y=4  

Answer 2

The generic equation of the line is:

$y-yo = m (x-xo)$

Where,

m: slope of the line

(xo, yo): ordered pair that belongs to the line

The slope of the line is given by:

$m = \frac{4-4}{3 - (- 1)}$

$m = \frac{4-4}{3 + 1}$

$m = \frac{0}{4}$

$m = 0$

By choosing an ordered pair we have:

$(xo, yo) = (3,4)$

Then, replacing values we have:

$y-4 = 0 (x-3)$

Rewriting we have:

$y = 4$

Answer:

The equation of the line is:

$y = 4$