Respuesta :
[tex]Hi \\ \\ 3x\²-7x+4 ~~--\ \textgreater \ \boxed{\frac{-b\pm \sqrt{b\²-2ac} }{2a} } \\ a=3 \\ b=-7 \\ c=4 \\ \\ x= \frac{7\pm \sqrt{(-7)\²-2.3.4 } }{2.(3)} \\ \\ x= \frac{7\pm5}{6} \begin{cases}x_1= \frac{7+5}{6}=2 \\ \\ x_2= \frac{7-5}{6}= \frac{1}{3} \end{cases} \\ \\ \therefore~(2; \frac{1}{3}) \\ \\ \\ [/tex]