Question

an image of a snowflake is 1.8 centimeters wide if the actual snowflake is 1/8 the size of the image what is the width of the actual snowflake express your answer in decimal

Answer 1

1.8 * 1/8 = 0.225, so the width is 0.225 cm. ;)

Answer 2

0.225 centimeters

Further explanation

Given:

• An image of a snowflake is 1.8 centimeters wide.  
• The actual snowflake is $\frac{1}{8}$ the size of the image.

Question:

What is the width of the actual snowflake?

The Process:

Since the actual snowflake is part of the image size by $\frac{1}{8}$ part, let us make a model of the image and the actual snowflake.

• The image of a snowflake: $\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot } \rightarrow 1.8 \ cm$  
• The actual snowflake: $\boxed{ \cdot } \rightarrow \frac{1}{8} \ of \ 8$

And now, let us calculate the width of the actual snowflake. As we know, the actual snowflake is $\frac{1}{8}$ the size of the image.

$\boxed{ \ = \frac{1}{8} \times 1.8 \ }$

$\boxed{ \ = \frac{1}{8} \times \frac{18}{10} \ }$

$\boxed{ \ = \frac{1 \times 18}{8 \times 10} \ }$

$\boxed{ \ = \frac{18}{80} \ }$

Both the numerator and denominator are divided by two to make it a simple fraction.

$\boxed{ \ = \frac{9}{40} \ }$

Both the numerator and denominator are multiplied by 25 to make it a decimal fraction. Therefore, the denominator will be 1,000.

$\boxed{ \ = \frac{9 \times 25}{40 \times 25} \ }$

$\boxed{ \ = \frac{225}{1,000} \ }$

Thus, the width of the actual snowflake is 0.225 centimeters.

Learn more

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2. What fraction of the box is left (Kim and Courtney)? brainly.com/question/37157
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