Question

At an animal shelter, there are 15 dogs, 12 cats, 3 snakes, and 5 parakeets. What percent less parakeets are there than dogs?

Answer 1

There are 35 total animals and 5 parakeets and 15 dogs. 15/35*100 is there percentage of dogs and 5/25*100 is the percentage of parakeets. (15-5)/35*100 is the percentage difference. Simplifying, this equals 28.571%

Answer 2

Answer:  The required percentage is 28.57%.

Step-by-step explanation:  Given that at an animal shelter, there are 15 dogs, 12 cats, 3 snakes, and 5 parakeets.

We are to find the percentage by which parakeets are less than dogs.

From the given information, the number of dogs is

$n_d=15,$

the number of parakeets is

$n_p=5.$

And, the total number of animals is

$n=15+1+3+5=35.$

So, the difference of the number of dogs and parakeets is

$N=n_d-n_p=15-5=10.$

Therefore, the percentage by which parakeets are less than dogs is

$\dfrac{N}{n}\times100\%=\dfrac{10}{35}\times100\%=\dfrac{200}{7}\%=28.57\%.$

Thus, the required percentage is 28.57%.