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The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 feet, the area will remain the same. Find the dimensions of the original rectangle.

Respuesta :

The dimensions of the original rectangle are as follows:

Length is 20ft and width is 12ft.

Given:

  • L=W+8
  •  (W+4)(L-5)=WL 

Find:

  • The dimension i.e., length and width of the original rectangle.

Solution:

Consider that the length of the rectangle is L and the width of the rectangle is W.

So, from the given equation, we get;

 WL-5W+4L-20=WL

4L-5W=20

⇒ 4(W+8)-5W=20

⇒4W+32-5W=20                

⇒W=32-20                  

W=12ft & L=20ft

Hence, The length is 20ft and the width is 12ft.

To learn how to calculate the length and width, refer to:

https://brainly.com/question/25292087

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