Question

Which is the completely factored form of 12x3 – 60x2 + 4x – 20?

Answer 1

$12x^3 - 60x^2 + 4x - 20 \\ \\ GCF = 4 \\ \\ 4( \frac{12x^3}{4} + \frac{-60x^2}{4} + \frac{4x}{4} - \frac{20}{4}) \\ \\ 4(3x^3 - 15x^2 + x - 5) \\ \\ 4(3x^2(x - 5) + (x - 5)) \\ \\ 4(x - 5)(3x^2 + 1)$

The final result is: 4(x - 5)(3x² + 1).