Question

How many grams of sucrose, C12H22O11, are in a 94.2 mL sample of a 2.6 M sucrose solution

Answer 1

First, convert molarity to moles by multiplying it by the volume in liters.
(2.6M)(.0942L)= .245mol sucrose

Then multiply it by the molar mass:
(.245mol sucrose)(342.3g/mol)= 83.8g sucrose