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zexius
Multiply [tex] \frac{3}{4} [/tex] by 2 to get a common denominator.

That'll then show you that [tex] \frac{3}{4} [/tex] is bigger, as:

[tex] \frac{3}{4} [/tex] × 2 = [tex] \frac{6}{8} [/tex]

and,

[tex] \frac{6}{8} [/tex] is bigger than [tex] \frac{3}{8} [/tex]
No, 3/4 is larger since if you used a common denominator of 8, 3/4 would be 6/8 and 3/8 would remain 3/8.
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