Answer: 0.17 kg
First we need to find the volume of the thin cylinder made up of aluminium.
Volume of cylinder, [tex]V= \pi r^2h\\ \Rightarrow V=3.14\times0.20^2\times\0.50\times10^{-3}m^3=6.28\times10^{-5}m^3[/tex]
Density of aluminium is [tex]\rho=2700 kg/m^3[/tex]
Mass of Aluminium sheet used in making this, [tex]M= Density \times volume[/tex]
[tex]\Rightarrow M=\rho\times V=2700 kg/m^3 \times6.28\times10^{-5}m^3=0.17 kg[/tex]
