v = hvh
Simplifying the above equation:
v = h × v × h
Taking the RHS 'v' to LHS
⇒ v ÷ v = h × h
⇒ 1 = h × h
⇒ 1 = [tex]h^{2}[/tex]
⇒ h = √1
⇒ h = [tex]\left \{ {{h=1} \atop {h=-1}} \right.[/tex]
So h can have the values +1 or -1.
Putting h = +1 in the equation,
v = (+1) × v × (+1)
⇒ v = v
Hence, v can take any integer value.
Putting h = -1 in the equation, when h = 1.
v = (-1) × v × (-1)
⇒ v = v
Hence, v can take any integer value when h = -1.
Hence, as long as h is either +1 or -1, v can take any integer value.
