22 + 0.25p = 47 -22. -22 0.25p= 25 Divide : 25_0.25 P= 100 To check you substitute 22 + 0.25(100)=47 22 + 25 =47 47 = 47 Matches
Answer:
The weight should be 100 pounds.
Step-by-step explanation:
Consider the provided equation.
[tex] 22+0.25p=c [/tex]
Where, the cost c in dollars that the store charges to deliver an application that weights p pounds.
We need to find the weight of that cost of $47 to deliver.
Substitute the value of c = 47 in the provided equation.
[tex] 22+0.25p=47 [/tex]
[tex] 0.25p=47-22 [/tex]
[tex] 0.25p=25 [/tex]
[tex] p=\frac{25}{0.25} [/tex]
[tex] p=100 [/tex]
Hence, the weight should be 100 pounds.