So with this polynomial, I will be completing the square. Firstly, what two terms have a product of 32x^2 and a sum of -12x? That would be -8x and -4x. Replace -12x with -4x - 8x: [tex] x^2-4x-8x+32 [/tex]
Next, factor x^2 - 4x and -8x + 32 separately. Make sure that they have the same quantity in the parentheses: [tex] x(x-4)-8(x-4) [/tex]
Now you can rewrite your expression as [tex] (x-8)(x-4) [/tex] , and your factors are (x - 8) and (x - 4).
