Respuesta :

=−a3b2c2−a2b3c2+a2b2c is the answer


Answer:   The required product is [tex]-a^3b^2c^2-a^2b^3c^2+a^2b^2c^3.[/tex]

Step-by-step explanation:  We are given to find the following product :

[tex]P=-a^2b^2c^2(a+b-c)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

We will be using the following property of exponents to find the give product :

[tex]x^a\times x^b=x^{a+b}.[/tex]

The product (i) can be calculated as follows :

[tex]P\\\\=-a^2b^2c^2(a+b-c)\\\\=-a^{2+1}b^2c^2-a^2b^{2+1}c^2+a^2b^2c^{2+1}\\\\=-a^3b^2c^2-a^2b^3c^2+a^2b^2c^3.[/tex]

Thus, the required product is [tex]-a^3b^2c^2-a^2b^3c^2+a^2b^2c^3.[/tex]

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