Question

i need to find the value of x and BC if B is between C and D

CB=4X-9, BD= 3X+5, and CD = 17

Answer 1

It is given in the question that B is in between C and D.

Therefore

$CB+ BD = CD$

Substituting the given values of CB,BD and CD, we will get

$4x-9+3x+5=17$

Combining like terms, we will get

$7x-4=17$

Now we need to move 4 to the right side by adding 4 to both sides, that is

$7x = 21 \\ x=3$