Question

Please help. I will give brainiest user.2b.Calculating Magnification: Magnification describes how much larger an object appears when viewed through a microscope than its actual size. The eyepiece and the objective lens are the two magnifying features of every microscope. Scanning objective=4x, Low-power Objective= 10X and High-Power=40X.(eyepiece magnifies image 10X(times) its actual size.

2c.Calculate the total magnification of the daphnia/water flea under each lens.

Eyepiece x Scanning Objective = Total Magnification

Eyepiece x Low-power Objective = Total Magnification

Eyepiece x High-power Objective = Total Magnification

Question: What is its actual size under each lens?

Answer 1

Given,  

Magnification of eyepiece = 10x  

Magnification of scanning objective = 4x  

Magnification of low power objective lens = 10x  

Magnification of high-power objective lens = 10x  

Magnification of the microscope can be determined by using the following formula:

$Mo \times Me = M$

[Where Mo is the magnification of the ocular lens and the Me is the magnification of eyepiece and M is total magnification]

Total magnification of Daphnia under scanning objective (Ms)

$Ms = (4 \times 10)x\\Ms = 40x$

Total magnification of Daphnia under low power objective lens (ML) $ML = (4 \times 10)x\\ML = 40x$

Total magnification of Daphnia under high power objective lens $M_{H}$

$MH = (4 \times 10)x\\MH = 40x$

An average size of daphnia is 3mm

So, Total magnification of Daphnia under scanning objective = 40x

Total size of daphnia after magnification would be =  $40 \times 3 = 120 mm$

Total magnification of Daphnia under low power objective lens = 100x Total size of daphnia after magnification would be =  $100 \times 3 = 300 mm$

Total magnification of Daphnia under high power objective lens = 400x Total size of daphnia after magnification would be = $400 \times 3 = 1200 mm$