Question

3\sqrt(54)-2\sqrt(24)-\sqrt(96)+4\sqrt(63)

Answer 1

$3\sqrt(54)-2\sqrt(24)-\sqrt(96)+4\sqrt(63)$

We simplify each term and then combine it

$3\sqrt(54) = 3 *\sqrt{9*6} = 3*3 \sqrt{6} = 9\sqrt{6}$

$-2\sqrt(24) = -2\sqrt{4*6} = -2*2\sqrt{6} = -4\sqrt{6}$

$-\sqrt(96) = -\sqrt{16*6} = -4\sqrt{6}$

$4\sqrt(63) = 4\sqrt{9*7} = 4* 3\sqrt{7} = 12\sqrt{7}$

$9\sqrt{6} -4\sqrt{6} -4\sqrt{6} + 12\sqrt{7}$

$\sqrt{6} + 12\sqrt{7}$