The perimeter of the larger rectangle is 126 cm.
Explanation
The ratio of the corresponding sides of two similar rectangles is [tex]4:9[/tex]
Given that, the length of the smaller rectangle is 16 cm and its width is 12 cm
Lets assume, the length and width of larger rectangle are [tex]x[/tex] and [tex]y[/tex] respectively.
(Length of smaller / Length of larger) = 4 : 9
[tex]\frac{16}{x}=\frac{4}{9}\\ \\ 4x = 16*9\\ \\ 4x= 144 \\ \\ x= \frac{144}{4}=36[/tex]
So, the length of larger rectangle is 36 cm.
(Width of smaller / Width of larger) = 4 : 9
[tex]\frac{12}{y}=\frac{4}{9}\\ \\ 4y= 12*9\\ \\ 4y= 108\\ \\ y= \frac{108}{4}=27[/tex]
So, the width of larger rectangle is 27 cm.
Thus, the perimeter of the larger rectangle [tex]=2(length+width)= 2(36+27)= 2(63)=126 cm.[/tex]