Using our two points, we can solve for the distance as such:
[tex] \sqrt{(4-(-6))^2+(3-(-1))^2}\\ \sqrt{(10)^2+(4)^2}\\ \sqrt{100+16}\\ \sqrt{116} [/tex]
Now our exact answer may be √116, however using the product rule of radicals we can further simplify the radical as such:
√116 = √4 x √29 = 2√29.