Points B, O, Y are collinear on BY, and BO:OY=5/8. B is located at (4,2), O is located at (7, -3) and Y is located at (x,y). Determine the values x and y

Points B O Y are collinear on BY and BOOY58 B is located at 42 O is located at 7 3 and Y is located at xy Determine the values x and y class=

Respuesta :

Answer:

x = [tex] \frac{59}{5}  [/tex]

y = -11

Explanation:

Given that a line segment BY. O is the point lies between B & Y.

Ratio is BO:OY = 5:8

Coordinate of point B = (4,2)

Coordinate of point O = (7,-3)

We will find the coordinate of Y (x,y)

Here we use the section formula.

Internal section formula is :

[tex] Y(x,y) =(\frac{mx_{2}+nx_{1}}{m + n},\frac{my_{2}+ny_{1}}{m + n})  [/tex]

(7,-3) =[tex]  (\frac{5*x+8*4}{5+8} ,\frac{5*y+8*2}{5+8} )   [/tex]

(7,-3) = [tex]  (\frac{5x+32}{13}, \frac{5y+16}{13})  [/tex]

Now

7  = [tex] \frac{5x+32}{13}  [/tex]  

5x+32 = 91

x = [tex] \frac{59}{5}  [/tex]

and

[tex] -3 =\frac{5y+16}{13}   [/tex]

5y + 16 = -39

y = -11

That's the final answer.

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