Points B, O, Y are collinear on BY, and BO:OY=5/8. B is located at (4,2), O is located at (7, -3) and Y is located at (x,y). Determine the values x and y

Answer:
x = [tex] \frac{59}{5} [/tex]
y = -11
Explanation:
Given that a line segment BY. O is the point lies between B & Y.
Ratio is BO:OY = 5:8
Coordinate of point B = (4,2)
Coordinate of point O = (7,-3)
We will find the coordinate of Y (x,y)
Here we use the section formula.
Internal section formula is :
[tex] Y(x,y) =(\frac{mx_{2}+nx_{1}}{m + n},\frac{my_{2}+ny_{1}}{m + n}) [/tex]
(7,-3) =[tex] (\frac{5*x+8*4}{5+8} ,\frac{5*y+8*2}{5+8} ) [/tex]
(7,-3) = [tex] (\frac{5x+32}{13}, \frac{5y+16}{13}) [/tex]
Now
7 = [tex] \frac{5x+32}{13} [/tex]
5x+32 = 91
x = [tex] \frac{59}{5} [/tex]
and
[tex] -3 =\frac{5y+16}{13} [/tex]
5y + 16 = -39
y = -11
That's the final answer.