Question

1. If 3(x+1)=7 find the value of 3x

2.  if -3(y-1)=9 find the value of 1/2y 

3. if 4-7x=39 find the value of x+1

Answer 1

1)

3(x + 1) = 7

3.x + 3.1 = 7

3x + 3 = 7

3x = 7 - 3

3x = 4

x = $\frac{4}{3}$

3x = 3.\frac{4}{3}[/tex]

3x = 4

2)

-3(y - 1) = 9

-3.y - 3 . (-1) = 9

-3y + 3 = 9

-3y = 9 - 3

-3y = 6

y = 6/-3

y = -2

$\frac{1}{2}y=\frac{1}{2}.(-2)$

$\frac{1}{2}y=-1$

3)

4 - 7x = 39

-7x = 39 - 4

-7x = 35

x = 35/-7

x = -5

x = -5

x + 1 = -5 + 1

x + 1 = -4