Question

Ezra works two summer jobs to save for a laptop that costs at least $1100. He charges $15/hr to mow lawns and $10/hr to walk dogs. This situation is modeled by: 15x + 10y ≥ 1100.

Suppose Ezra decides to also spend more than $80 on a printer. The inequality becomes

15x + 10y


.

Answer 1

$\\ \text{Ezra works two summer jobs to save for a laptop that costs at least }\ 1100\\ \\ \text{also given that he charges 15 dollars per hour to mow lawns and }\\ \text{10 dollars per hour to walk dogs.}\\ \\ \text{so if he mow lawns for x hours and walk the dogs for y hours in summer,}\\ \text{then the inequality that modeles this data is}\\ \\ 15x+10 y \geq 1100$

$\text{now suppose Ezra decides to also spend more than }\ 80 \text{ on a printer,}\\ \text{so the total expences he want for laptop and printer is}=1100+80=1180\\ \\ \text{so now the inequality becomes: }$

15 x+10 y >1180

Answer 2

Answer:

It becomes 15x + 10y > 1180

If a stays the same, b must be greater than its previous value to satisfy the new inequality.

Now suppose b stays the same. Then, a must be greater than its previous value to satisfy the new inequality.

How is the graph if the solution affect?

- The boundary line becomes dashed

- the boundary line is translated vertically