Question

A gas sample occupies 3.25 liters at 297.5K and 2.4 atm. Determine the temperature at which the gas will occupy 4.25 L at 1.50 atm.

what is the answer of this

Answer 1

By combining the three laws: Boyle's, Charles', and Gay-Lussac's Laws we get the combined gas law that is:

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

where $P$ is pressure, $V$ is volume,  and $T$ is temperature.

$P_1 = 2.4 atm, V_1 = 3.25 L, T_1 = 297.5 K$

$P_2 = 1.50 atm, V_2 = 4.25 L$

Substituting the values,

$\frac{2.4 atm\times 3.25 L}{297.5 K} = \frac{1.5 atm \times 4.25 L}{T_2}$

${T_2} = \frac{1.5 atm \times 4.25 L\times 297.5 K}{2.4 atm\times 3.25 L}$

${T_2} = 243.149 K$

Thus, the temperature is ${T_2} = 243.149 K$.