Respuesta :

gmany

[tex] \dfrac{3n^2-n}{n^2-1}\div\dfrac{n^2}{n+1}=\dfrac{n(3n-1)}{n^2-1^2}\cdot\dfrac{n+1}{n^2}=\dfrac{3n-1}{(n-1)(n+1)}\cdot\dfrac{n+1}{n}\\\\=\dfrac{3n-1}{n-1}\cdot\dfrac{1}{n}=\dfrac{3n-1}{n^2-n} [/tex]

[tex]Used:\\\\a^2-b^2=(a-b)(a+b)[/tex]

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