Question

The osmotic pressure, π, of a solution of glucose is 132 atm . find the molarity of the solution at 298 k.

Answer 1

The formula for osmotic pressure is:

$\Pi = iMRT$

where $\Pi$ is osmotic pressure, $i$ is van't Hoff's factor, $M$ molarity, $R$ is Ideal gas constant, and T is Temperature.

$\Pi  $ = 132 atm

The van't Hoff's factor for glucose, $i$ = 1

$R = 0.08206 Latmmol^{-1}K^{-1}$

$T = 298 K$

Substituting the values in the above equation we get,

$132 atm = 1\times M\times 0.08206 Latmmol^{-1}K^{-1}\times 298$

$M = \frac{132 atm}{1\times 0.08206 Latmmol^{-1}K^{-1}\times 298} = 5.4797 molL^{-1} \simeq 5.48 molL^{-1}$

So, the molarity of the solution is $5.48 molL^{-1}$.