Question

A car traveling in a straight line has a velocity of 6.64 m/s at some instant. after 5.55 s, its velocity is 10.9 m/s. what is its average acceleration in this time interval?

Answer 1

We calculate the average acceleration by formula,

$a_{avg}= \frac{v_{i}-v_{f}}{\Delta t}\      $

Here vi  is initial velocity of the car and after given time its velocity becomes vf .

According to question,

$v_{i} = 6.64 m/s,$

$v_{f} = 10.9m/s$,

$\Delta t =5.55s$

Therefore, putting these values in above equation, we get

 a_{avg} = \frac{10.9 m/s - 6.64 m/s}{5.55 s}  

[/tex]$a_{avg}= \frac{4.26 m/s }{5.55 s}

$$a_{avg} = 0.77 m/s^2  $}}

Thus, the average acceleration in given time interval is $  0.77 m/s^2$