Question

e bisects df, de=2y, and ef=8y-3. find de, ef, and df

Answer 1

de is congruent to ef definition of bisector

de = ef definition of congruency

2y = 8y - 3 substitution

-6y = -3 subtraction property (subtracted 8y)

y = $\frac{1}{2}$ division property (divided by -6)

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de = 2y = 2($\frac{1}{2}$ ) = 1

ef = 8y - 3 = 8($\frac{1}{2}$ ) - 3 = 4 - 3 = 1

de + ef = df segment addition postulate

1 + 1 = df substitution

2 = df simplify

Answer: de=1, ef=1, df=2