In this question, we have a point given which is (3,6) and a slope, m which is -3/4 .
Now we use slope intercept form, which is
[tex] y= mx +b [/tex]
Where m is the slope and b is the y intercept.
Substituting the point for x and y, and the value of m, we have to solve for b , that is
[tex] 6 = \frac{-3}{4}*3 +b [/tex]
[tex] b = 6 + \frac{9}{4} = \frac{33}{4} [/tex]
Substituting the values of m and b in slope intercept form, we will get
[tex] y = \frac{-3}{4}x + \frac{33}{4} [/tex]