Question

A train is traveling at a constant speed of 105 miles per hour. How many feet does it travel in 4 seconds? Remember that 1 mile is 5280 feet.

Answer 1

Distance cover in 4 seconds in feet is 6,160 feet

Given that;

1 mile = 5280 feet

Speed of train = 105 miles per hour

Find:

Distance cover in 4 seconds in feet

Computation:

$Distance\ cover\ in\ 4 \ seconds\ in\ feet = [\frac{105 \times5280 }{60\times60}]4 \\\\Distance\ cover\ in\ 4 \ seconds\ in\ feet = [\frac{5,54,400}{360}]4 \\\\Distance\ cover\ in\ 4 \ seconds\ in\ feet = [1540]4 \\\\Distance\ cover\ in\ 4 \ seconds\ in\ feet = 6160 feet$

Learn more:

https://brainly.com/question/23774048?referrer=searchResults