We can solve this problem by converting units and then canceling units so that we get distance:
[tex] (\frac{3.0x10^{8}m}{s} )*(\frac{8.3min}{1} )*(\frac{60s}{1min} )=1,494x10^{8}m=1.49x10^{11}m [/tex]
So therefore we know that the earth is [tex] 1.49x10^{11} [/tex] meters away from the sun.