Respuesta :
note that this isn't a summation problem, it just wants to find on what day will she get 10,000,000 dollars in 1 day
convert that the pennies to make it easier (100 pennies=1 dollar so that's 1,000,000,000 or a billion pennies) (note that 1,000,000,000=10^9)
each day is 3 times of the other
first day is 1, 2nd is 1*3, 3rd day is 1*3*3, 4th day is 1*3*3*3, etc
hmm, so after n days, the number of pennies is [tex]1*3^{n-1}[/tex]
one long way is to keep dividing by 3 to find how many times we need to do that to find n
easier way is to do this:
1,000,000,000=[tex]3^{n-1}[/tex]
take ln of both sides
[tex]ln(1,000,000,000)=ln(3^{n-1})[/tex]
[tex]ln(10^9)=ln(3^{n-1})[/tex]
use properties of logarithms
[tex]9ln(10)=(n-1)ln(3)[/tex]
divide both sides by ln(3)
[tex]\frac{9ln(10)}{ln(3)}=n-1[/tex]
add 1 to both sides
[tex]\frac{9ln(10)}{ln(3)}+1=n[/tex]
using your calculator we get 19.863=n
so after 19.863 days
but we need a whole number of days so round up to 20
20 days
it will be on day 20 of the month