B. 3501 yds
C. 1632 yds
D. 3181 yds
![B 3501 yds C 1632 yds D 3181 yds class=](https://us-static.z-dn.net/files/d39/2da35c7d8982793acf13eb4d112d465e.png)
Since we are given two angles of a triangle, we can find the third angle.
180 - 38 - 57 = 85
The angle of the triangle at the Voyager is 85 deg.
We also know the length of the side opposite the Voyager, so we have enough information to establish a ratio in the law of sines.
[tex] \dfrac{a}{\sin A} = \dfrac{b}{\sin B} [/tex]
[tex] \dfrac{2640~yd}{\sin 85^\circ} = \dfrac{x}{\sin 38^\circ} [/tex]
[tex] x = \dfrac{2640~yd~\sin 38^\circ}{\sin 85^\circ} [/tex]
[tex] x = 1632~yd [/tex]
Answer: C. 1632 yd