Respuesta :
From 1st EQ. of uniform motion
1)20.9-3.44/6=t=2.91 sec
2)28= 0+4.22a
a=6.66m/sec^2
3) Instantaneous acceleration
1)20.9-3.44/6=t=2.91 sec
2)28= 0+4.22a
a=6.66m/sec^2
3) Instantaneous acceleration
Answer: a) 2.91s b) 6.64m/s² c) Instant acceleration
Explanation:
a) Acceleration is defined as the change in velocity of an object with respect to time. Mathematically,
Acceleration = change in velocity/time
Change in velocity = final velocity-initial velocity
Acceleration (a) = final velocity (v)/-initial velocity(u)/time(t)
Given final velocity = 20.9m/s
Initial velocity = 3.44m/s
Acceleration = 6m/s²
Time =?
Substituting in the formula we have;
6 = 20.9-3.44/t
6t = 17.46
t = 17.46/6
t = 2.91seconds
b) using the same formula for acceleration in a above;
a = v-u/t
Given v = 28m/s u = 0m/s(since it starts from rest) t = 4.22seconds
a = 28-0/4.22
a = 6.64m/s²
c) The change in velocity that occurs at a specific moment in time is known as Instant acceleration.
We know that acceleration is change in velocity with respect to time. If the acceleration now happens at a specific moment, it is known as instant acceleration i.e acceleration of the body at that instance