Question

A bike tire has a diameter of 27 inches. What distance is covered in 10 rotations of the tire? Round to the nearest tenth.

Answer 1

For each rotation of the tire, the wheel axle moves forward by a distance equal to the circumference of the tire.

Here, that circumference is C = pi*d, where d is the wheel diameter:

C = pi(27 in) = 27 pi inches.

The distance covered in 10 rotations of the wheel is thus 10(27 pi inches) = 270 pi inches. To the nearest tenth, that's 848.2 inches.