From given picture we can see that X is mid point of line PQ
So PQ=2PX
From given picture we can see that Y is mid point of line PR
So PR=2PY
Now consider triangles PRQ and PYX
Sides PQ and PX has same ratio as of sides PR and PY (as calculated above)
angle XPY= angle QPR (common angle)
Hence triangles PRQ and PYX are similar.
We know that ratio of the sides of similar triangles is always equal so we can write:
[tex] \frac{PQ}{PX} = \frac{QR}{XY} [/tex]
Plug the given values QR=8 and PQ=2PX
[tex] \frac{2PX}{PX} = \frac{8}{XY} [/tex]
[tex] \frac{2}{1} = \frac{8}{XY} [/tex]
[tex] 2 = \frac{8}{XY} [/tex]
[tex] XY = \frac{8}{2} [/tex]
[tex] XY = 4 [/tex]
Hence final answer is XY = 4 units.