Let's call the integers [tex] x [/tex] and [tex] y [/tex]. The first information (one is twice the other) translates as [tex] x = 2y [/tex].
The second information about the sum of reciprocals can be written as
[tex] \dfrac{1}{x}+\dfrac{1}{y} = \dfrac{3}{10} [/tex]
But since we know that [tex] x = 2y [/tex], we can rewrite this expression as
[tex] \dfrac{1}{2y}+\dfrac{1}{y} = \dfrac{3}{2y} = \dfrac{3}{10} [/tex]
Since the numerators of both fractions equal 3, then the denominators must be equal as well. So, we have
[tex] 2y = 10 \implies y = 5 [/tex]
And since we know that [tex] x = 2y = 2\cdot 5 = 10 [/tex].