Question

Find the dimensions of a rectangle whose perimeter is 18 meters and whose area is 20 square meters.

Answer 1

call the length L and there width W. then perimeter is 2L+2W=18. area is LW=20.

2L+2W=18
L+W=9
LW=20
L=9-W
(9-W)W=20
W²-9W+20=0
(W-5)(W-4)=0
W=4,5

rectangle is 4by5

Answer 2

Dimensions of a rectangle is 4 meter and 5 meter.

Given that:

Perimeter of rectangle = 18 meter

Area of rectangle = 20 square meters

Find:

Dimensions of a rectangle

Computation:

Perimeter of rectangle = 2[l + b]

2[l + b] 18

l + b = 9 ........ eq1

Area of rectangle = [l][b]

[l][b] = 20 ...... eq2

From equation 1 and 2

l = 4, 5

b = 4, 5

So,

Dimensions of a rectangle = 4, 5 meter

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