Question

The distance between the points (6, b0 and (2, -4) is 4 to the sqaure root of five. find the value of b

Answer 1

√(6-2)² + (b+4)² = 4√5

√16+b²+8b+16 =√80

b²+8b+32=80

b² + 8b - 48 = 0

(b+12)(b-4)=0

b can be-12 or 4