Question

If a triple beam balance shows a weight of 100g on one beam, 20g on another beam, and 1g on the third beam, what is the weight of the object?

Answer 1

Answer:

1.186 N

Explanation:

First of all, we need to calculate the mass of the object, which is given by the sum of the three readings on the three different beams:

m = 100 g + 20 g + 1 g = 121 g

Now let's convert into kilograms:

m = 121 g = 0.121 kg

And now we can calculate the weight with the formula:

W = mg

where

m = 0.121 kg is the mass

g = 9.8 m/s^2 is the acceleration of gravity

Substituting,

$W=(0.121)(9.8)=1.186 N$