The number of sandwiches that can be prepared is
... min(52/2, 75/3) = min(26, 25) = 25
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[tex]\dfrac{1\,\text{sandwich}}{2\,\text{bread slices}}\times(52\,\text{bread slices})=\dfrac{52}{2}\,\text{sandwich}\\\\=26\,\text{sandwich}\\\\\\\text{Likewise}\\\dfrac{1\,\text{sandwich}}{3\,\text{cheese slices}}\times(75\,\text{cheese slices})=\dfrac{75}{3}\,\text{sandwich}\\\\=25\,\text{sandwich}[/tex]
Answer:
25 sandwiches whole cheese sandwiches that can be prepared from 52 slices of bread and 75 slices of cheese
Step-by-step explanation:
No. of sandwiches can be made using 2 slices of bread = 1
No. of sandwiches can be made using 1 slices of bread =[tex]\frac{1}{2}[/tex]
No. of sandwiches can be made using 52 slices of bread =[tex]\frac{1}{2} \times 52[/tex]
=[tex]26[/tex]
No. of sandwiches can be made using 3 slices of cheese = 1
No. of sandwiches can be made using 1 slices of cheese =[tex]\frac{1}{3}[/tex]
No. of sandwiches can be made using 75 slices of cheese =[tex]\frac{1}{3} \times 75[/tex]
=[tex]25[/tex]
Minimum of 26 and 25 is 25
So, 25 sandwiches whole cheese sandwiches that can be prepared from 52 slices of bread and 75 slices of cheese
